(2y-1)^(2)=(17+y)(17-y)

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Solution for (2y-1)^(2)=(17+y)(17-y) equation: 



(2y-1)^(2)=(17+y)(17-y)

We move all terms to the left:

(2y-1)^(2)-((17+y)(17-y))=0

We add all the numbers together, and all the variables

(2y-1)^2-((y+17)(-1y+17))=0

We multiply parentheses ..

-((-1y^2+17y-17y+289))+(2y-1)^2=0



We calculate terms in parentheses: -((-1y^2+17y-17y+289)), so:

(-1y^2+17y-17y+289)

We get rid of parentheses

-1y^2+17y-17y+289

We add all the numbers together, and all the variables

-1y^2+289

Back to the equation:

-(-1y^2+289)



We get rid of parentheses

1y^2+(2y-1)^2-289=0

We add all the numbers together, and all the variables

y^2+(2y-1)^2-289=0

We move all terms containing y to the left, all other terms to the right

y^2+(2y-1)^2=289

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